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asm1 picoCTF 2019 Solution

Trace through x86 assembly code by hand to determine what value a function returns for a given input.

Published: April 2, 2026Updated: August 13, 2026

Description

What does asm1(0x345) return? Trace through the provided x86 assembly. Submit the flag as a hexadecimal value.

Download the assembly file.

bash
wget <url>/test.S

Solution

Want to try it yourself first?

The guided walkthrough reveals hints one step at a time.

Walk me through it
  1. Step 1Read the assembly and set up the stack frame
    Observation
    The challenge gives a raw .S assembly file and asks what the function returns for a given input. Step one is reading it to find where the argument 0x345 lives, which in 32-bit cdecl means on the stack.
    Open test.S. The function asm1 takes one argument (0x345 = 837). Trace through it manually: set up the stack frame in your head (or on paper), tracking the value of eax and other registers at each instruction.
    bash
    cat test.S
    What didn't work first

    Tried: Running 'objdump -d test.S' to disassemble and read the function flow.

    objdump -d disassembles compiled binaries, not raw .S source. Point it at an uncompiled .S file and you get nothing useful. Just open the file with cat or an editor: AT&T-syntax assembly is already readable.

    Tried: Assuming the first argument is in eax or edi (System V AMD64 convention) rather than on the stack.

    This is 32-bit x86 cdecl, not the 64-bit System V ABI. In cdecl the arguments are pushed on the stack before the call, so the first one sits at [ebp+8] after the standard prologue. Reading edi or eax instead gives garbage.

    Learn more

    In x86 calling convention (cdecl), arguments are pushed on the stack right-to-left. The first argument is at [ebp+8] after the function prologue (push ebp; mov ebp, esp). The return value is in eax when the function returns.

    Key x86 instructions: cmp a, b sets flags based on a - b. jg jumps if greater (signed). jl jumps if less. je jumps if equal. add and sub modify a register. mov copies a value.

  2. Step 2Trace the function logic
    Observation
    The function is a chain of cmp instructions against fixed values followed by conditional jumps (jg, jl, je). Following the one branch that 0x345 actually takes tells you what eax holds at ret.
    Start with the argument value 0x345 in [ebp+8]. Follow each branch condition (compare the argument to hardcoded values) to determine which branch is taken. Track the final value loaded into eax before ret.
    Learn more

    Compile the assembly and run it to verify your answer: gcc -m32 -o test test.S -no-pie && python3 -c "import ctypes; lib=ctypes.CDLL('./test'); print(hex(lib.asm1(0x345)))". This is often faster than manual tracing for complex functions.

  3. Step 3Submit the return value as the flag
    Observation
    The problem statement asks for the result in hexadecimal, so the eax value from the trace is the answer, formatted as picoCTF{0x...}.
    The return value in hex is the flag. Wrap it in picoCTF{...} if required, or submit it directly as a hex number.
    Learn more

    Reading x86 assembly is a fundamental reversing skill. Automated tools like Ghidra and IDA Pro decompile assembly to C-like pseudocode, but understanding the raw assembly allows you to verify and correct the decompiler output.

Interactive tools
  • Hex ViewerView text or raw hex bytes as a xxd-style hex dump with byte offset, hex columns, and ASCII sidebar. Highlights printable characters and null bytes.
  • Number Base ConverterConvert numbers between binary, octal, decimal, and hexadecimal instantly. Enter any value and see all four bases update in real time.

Flag

Reveal flag

picoCTF{0x348}

asm1(0x345): the argument 0x345 is compared against 0x37a, found smaller, so the function adds 3 and returns 0x348.

Key takeaway

Reading x86 assembly by hand is the foundation of reverse engineering: every compiled binary is assembly underneath, and knowing the calling convention lets you reason about any function whatever language it started as. A cmp followed by jg, jl, or je is just if/else, so tracing one input through the branches is mechanical once the flag register makes sense. The same skill carries into malware analysis, license-check bypasses, and firmware auditing, where source is never available.

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